Missus was reading a woman's article about this woman with massive jugs and it said they weighed in at 5Kg which got me thinking. Aside from lobbing them out onto some scales, how would they know what they weighed? I mean, the mammories would still be attached to the body so what compensation factor would you use for that fact. Chopping them off to weigh them isn't really an option unless the person is already deceased so how could they be accurately weighed. If they were perfectly spherical I suppose you could use the calculation for the volume of a sphere and then multiply by the specific gravity of a tit but who would know that any way. Amazing how your mind starts to wander innit?
Depends if you could fit Hemmsy n Dyson on a set of scales big enough am here all week (except Xmas Day n Boxing Day)
Been giving it some thought I reckon one of those latex rubber casts they use for producing bronze statues would work. Daub the latex over the breasts, let it set and slowly peel it off taking care not to rip it. Weigh the mould on a balance and then fill it with saline which I reckon is going to be around the same density as a tit. Subtract the gross weight from the mould weight and hey presto, an accurate weight of a pair of tits. All we need now is a volunteer to test the theory.
well I would just ask JLWBL..he would get it right to within a gramme he is our resident expert I would say.
Re: Been giving it some thought "All we need now is a volunteer to test the theory". Sorry to interject - but my wife (who has worryingly been following this thread) says unless you use a dead body and subsequently remove said items and compare against the dervied net weight how would you know if you were right?
Eureka Just dawned on me - "Archimedes displacement principle" which states that any object, wholly or partially immersed in a fluid, is buoyed up by a force equal to the weight of the fluid displaced by the object. In layman's terms - Get a bucket brim full of water, get her to totally immerse her tits in the water and collect the water displaced. The weight of the water displaced will be the weight of the pair of tits immersed in the bucket assuming they have the same density. I knew that GCSE in General Science would come in handy one day.
Re: Been giving it some thought Good point that. I think we'd need the volunteer to be somebody on their death bed.
Re: Eureka She's at it again!! "Tits are NOT water but contain a considerable amount of fat...so the density is not the same!! Smart-ar*e woman!!
Re: Eureka Apparently your principle is reasonable but ... Breast tissue is less dense than water. Multiply the weight of the water by 0.9 to compensate for this Also weigh each one separately as breasts are NOT symmetrical!
Re: Eureka I've no problems with weighing them separately but the displacement will take care of them both at the same time. e.g. if one was 500 cubic cm and the other 480 cu cm, the amount of water displaced would be 980 cubic cm. Using your factor for the density of a breast of 0.9 then the total weight would be 980 x 0.9 = 882 grammes. I think we might be onto something here mate. Theoretically we could also work out the volume of the woman's 5Kg tits by dividing by the density
It seems that cup size equates to a certain amount of body flesh/fat. Apparently a pound equals 454 grams, which is equal to 3 cup sizes, so one cup size equals 151.33 recurring grams. Therefore multiply the cup size by 151.33 to get the weight of the tits in grams. European manufacturers tend to use a standard AA, A, B, C, D, E, F, G, H, ... scale thus avoiding the DD, DDD, EE confusion. I reckon a AA size pair of tits weigh 151.33 grams, an A pair 302.66 grams and so on. I may be wrong though.
Re: Been giving it some thought they only need to be hand weighed IMO,anything else is a waste of time.
Re: Been giving it some thought get one in each hand and jiggle `em up and down shouting "whaaay" job done hope THIS helps