can anybody show me how to find x in this quadratic eqaution: 2xsquared+17x+8=0??? :S Cumon ne maths genius's out there, nows your chance to shine!!!
For all quadratic equations (axsquared + bx + c = 0) you can find the solution with the following formula: In this case, a=2; b=17; c=8 --> x = -1/2 OR x = -8
You have to divide it to two (or more) first degree terms, and find the x for both of them. If I knew the mathematical terminology in English any better then I'd be able to help, but now someone else has to explain this to you. :S Does the formula that I suggested look any familiar to you? Perhaps you could use that instead...
RE: What happened to the 17? Rite, am getting a little lost here, can someone, put it step by step on how to calculate this equation??
Sorry, I went off to do something else without explaining it.... The quadratic equation can be shown in two forms ax^2+bx+c=0 or (px+q)(rx+s)=0 a,b,c,p,q,r and s are ordinary numbers and ^2 means squared (or "to the power of 2") p multiplied by r makes a (in the example shown this is 2x1=2 or 1x2=2 so a and b are 1 and 2) q multiplied by s makes c (this could be either 1x8=8 or 2x4=8) p multiplied by s plus q multiplied by r equals b (this can only work if q times s is 1x8, if q times s is 2x4, then b would equal 10 Hope that helps, and sorry if it's a bit late!
(2x+1)(x+8)=0, 2x*(x+8)+1(x+8)=0 2x^2+16x+1x+8=0 2x^2+17x+8=0 write it down in reverse for a solution
thar an enigma, thee, Tomi..... Tha's obviously got some brains, and yet art on all Europe tha chose Barnsley ter suppooart........fookin ell
