</p> <font size="2">The way I see it is - There are 256 squares. So the first calculation, for therotational position of each square,is 4 to the power of 256. Which is pretty big.</font></p> <font size="2">Then you have to take into consideration that any square could be in any position on the board so I reckon you have to go 256 to the power of 256.</font></p> <font size="2">So do the permutations total (4 to the power of 256) + (256 to the power of 256) or 4 to the power of 256 to the power of 256 to the power of 256?</font></p> <font size="2">And how do I "to the power of" properly with this keyboard.</font></p>
By the way.... </p> <font size="2">...this is 4 to the power of 52 -</font></p> <font size="2">81,129,638,414,606,681,695,789,005,144,064</font></p> <font size="2">That's 81 bummerillion in old money.</font></p>