Will Howard be back in the team on Tuesday?

Discussion in 'Bulletin Board ARCHIVE' started by RichK, Apr 12, 2008.

  1. RichK

    RichK Well-Known Member

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    #1 RichK, Apr 12, 2008
    Can't really change that line up. Who do you drop? If he sticks with same formation then it has to be JCR or Leon. Wouldn't want to leave either out. Tough decision for SD.
     
  2. dreamboy3000

    dreamboy3000 Well-Known Member

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    #2 dreamboy3000, Apr 12, 2008
    Hopefully Just On The Bench

    Nobody deserves to be dropped and nobody should be guaranteed a first team place.
     
  3. Dan

    DanT Active Member

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    #3 DanT, Apr 12, 2008
    i'd like to see him leave brian on the bench but i honestly don't think he's got the stones, especially when he'll be trying to convince him to stay for next season
     
  4. Spa

    Spartacus Well-Known Member

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    #4 Spartacus, Apr 12, 2008
    without a doubt

    Heard Davey on the radio and he basically said different games require different approaches.

    Howard was only rested today to prevent a booking and subsequent suspension IMHO

    After tomorrow, IIRC, a booking wont mean a suspension.

    4-4-2 on tuesday I'll wager
     
  5. bfc

    bfcbub Active Member

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    #5 bfcbub, Apr 12, 2008
    he will be in for JCR nt
     
  6. Spa

    Spartacus Well-Known Member

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    #6 Spartacus, Apr 12, 2008
    possibly

    JCR was poor 1st half, improved later on.
     
  7. Arn

    Arnside Red Well-Known Member

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    #7 Arnside Red, Apr 12, 2008
    yes but he was played infield, and he's not effective there

    :eek:
     
  8. pon

    pontyender Well-Known Member

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    #8 pontyender, Apr 12, 2008
    A radical thought!

    What about playing Howard just off a central striker? Take your pick - Oddjob or Macken.
     
  9. funnyfella23

    funnyfella23 Well-Known Member

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    #9 funnyfella23, Apr 12, 2008
    Let him rest another game? He will still get paid of course
     
  10. Xer

    Xerxes Well-Known Member

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    #10 Xerxes, Apr 12, 2008
    He has to be. In place of Hassell.
     
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